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Difference between revisions of "Furnaces"

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====Metal Yields====
 
====Metal Yields====
−
(work in progress -Sprocket)
+
The base formula is MetalYield = OreAmount*3/100, that is for every 33.3 ore you put into the furnace you get 1 metal out. However due to the way the game rounds off this formula it is possible to get a significantly better yield by hitting the right "breakpoints".
 +
 
 +
For example, a good formula to use is 484 ore and 20 charcoal. That batch will smelt for 20 minutes and produce 15 charcoal. The table below shows the recipes that give the most beneficial round-off gains.
 +
 
 +
{| border="1"
 +
! Ore Used!! CC Used !! Metal Yield !! Ore Cost/Metal !! CC Cost/Metal !! Metal Yield/Hour !! Metal Yield/1000 Ore !! CC Cost/1000 ore !! Net Gain
 +
|-
 +
| 17
 +
| 20
 +
| 1
 +
| 17,0
 +
| 1,176
 +
| 3,0
 +
| 58,8
 +
| 1176,5
 +
| 96,1%
 +
|-
 +
| 50
 +
| 20
 +
| 2
 +
| 25,0
 +
| 0,400
 +
| 6,0
 +
| 40,0
 +
| 400,0
 +
| 33,3%
 +
|-
 +
|84
 +
|20
 +
|3
 +
|28,0
 +
|0,238
 +
|9,0
 +
|35,7
 +
|238,1
 +
|19,0%
 +
|-
 +
|117
 +
|20
 +
|4
 +
|29,3
 +
|0,171
 +
|12,0
 +
|34,2
 +
|170,9
 +
|14,0%
 +
|-
 +
|150
 +
|20
 +
|5
 +
|30,0
 +
|0,133
 +
|15,0
 +
|33,3
 +
|133,3
 +
|11,1%
 +
|-
 +
|184
 +
|20
 +
|6
 +
|30,7
 +
|0,109
 +
|18,0
 +
|32,6
 +
|108,7
 +
|8,7%
 +
|-
 +
|217
 +
|20
 +
|7
 +
|31,0
 +
|0,092
 +
|21,0
 +
|32,3
 +
|92,2
 +
|7,5%
 +
|-
 +
|250
 +
|20
 +
|8
 +
|31,3
 +
|0,080
 +
|24,0
 +
|32,0
 +
|80,0
 +
|6,7%
 +
|-
 +
|284
 +
|20
 +
|9
 +
|31,6
 +
|0,070
 +
|27,0
 +
|31,7
 +
|70,4
 +
|5,6%
 +
|-
 +
|317
 +
|20
 +
|10
 +
|31,7
 +
|0,063
 +
|30,0
 +
|31,5
 +
|63,1
 +
|5,2%
 +
|-
 +
|350
 +
|20
 +
|11
 +
|31,8
 +
|0,057
 +
|33,0
 +
|31,4
 +
|57,1
 +
|4,8%
 +
|-
 +
|384
 +
|20
 +
|12
 +
|32,0
 +
|0,052
 +
|36,0
 +
|31,3
 +
|52,1
 +
|4,2%
 +
|-
 +
|417
 +
|20
 +
|13
 +
|32,1
 +
|0,048
 +
|39,0
 +
|31,2
 +
|48,0
 +
|3,9%
 +
|-
 +
|450
 +
|20
 +
|14
 +
|32,1
 +
|0,044
 +
|42,0
 +
|31,1
 +
|44,4
 +
|3,7%
 +
|-
 +
|'''484
 +
|'''20
 +
|'''15
 +
|'''32,3
 +
|'''0,041
 +
|'''45,0
 +
|'''31,0
 +
|'''41,3
 +
|'''3,3%
 +
|-
 +
|500
 +
|19
 +
|15
 +
|33,3
 +
|0,038
 +
|47,4
 +
|30,0
 +
|38,0
 +
|0,0%
 +
|-
 +
|}
 +
''(The line in bold is the recommended recipe for common use)''
 +
 
 +
 
 +
Description of the columns of the table:
 +
{| border="1"
 +
! Column !! Description
 +
|-
 +
| Ore Used
 +
| How much ore you put into the furnace
 +
|-
 +
| CC Used
 +
| How much charcoal you put into the furnace
 +
|-
 +
| Metal Yield
 +
| How much metal you get out of the run
 +
|-
 +
| Ore Use/Metal
 +
| How much ore it cost to make 1 metal
 +
|-
 +
| CC Cost/Metal
 +
| How much charcoal it cost to make 1 metal
 +
|-
 +
| Metal Yield/Hour
 +
| How much metal you produce in an hour
 +
|-
 +
| Metal Yield/1000 Ore
 +
| How much metal you get out of 1000 ore
 +
|-
 +
| CC Cost/1000 Ore
 +
| How much charcoal it costs to smelt 1000 ore
 +
|-  
 +
| Net Gain:
 +
| How much metal you've gained compared to the baseline formula (MetalYield = OreAmount*3/100)
 +
|-
 +
|}
 +
 
 +
It's recommended to simply use the 484 ore + 20 cc => 15 metal recipe unless you want to squeeze some extra mileage out of your ore at a significant increase in charcoal costs. If you do want to save significantly on your ore you will have to go to the extreme recipes such as 50 ore + 20 cc => 2 metal or even 17 ore + 20 cc => 1 metal. By using the most ore-efficient recipe it's possible to almost double the metal yield by paying more than 25 times the charcoal cost.
 +
 
 
====Operation====
 
====Operation====
 
*Holds up to 500 ore
 
*Holds up to 500 ore

Revision as of 16:08, 27 December 2008

Bullet Furnace

Operation

Can load upto 5 charcoal, each charcoal provides 1 minute of additional Max FireTime.

It is possible to load less and start the reaction and then top it up, to a maximum of 5 over time.

it is a automatic process if you load max 5cc. just let it time out and collect.

Current "fire and forget" recipe is 50 ore, 5cc yields 1 metal.

Compression Furnace

Metal Yields

The base formula is MetalYield = OreAmount*3/100, that is for every 33.3 ore you put into the furnace you get 1 metal out. However due to the way the game rounds off this formula it is possible to get a significantly better yield by hitting the right "breakpoints".

For example, a good formula to use is 484 ore and 20 charcoal. That batch will smelt for 20 minutes and produce 15 charcoal. The table below shows the recipes that give the most beneficial round-off gains.

Ore Used CC Used Metal Yield Ore Cost/Metal CC Cost/Metal Metal Yield/Hour Metal Yield/1000 Ore CC Cost/1000 ore Net Gain
17 20 1 17,0 1,176 3,0 58,8 1176,5 96,1%
50 20 2 25,0 0,400 6,0 40,0 400,0 33,3%
84 20 3 28,0 0,238 9,0 35,7 238,1 19,0%
117 20 4 29,3 0,171 12,0 34,2 170,9 14,0%
150 20 5 30,0 0,133 15,0 33,3 133,3 11,1%
184 20 6 30,7 0,109 18,0 32,6 108,7 8,7%
217 20 7 31,0 0,092 21,0 32,3 92,2 7,5%
250 20 8 31,3 0,080 24,0 32,0 80,0 6,7%
284 20 9 31,6 0,070 27,0 31,7 70,4 5,6%
317 20 10 31,7 0,063 30,0 31,5 63,1 5,2%
350 20 11 31,8 0,057 33,0 31,4 57,1 4,8%
384 20 12 32,0 0,052 36,0 31,3 52,1 4,2%
417 20 13 32,1 0,048 39,0 31,2 48,0 3,9%
450 20 14 32,1 0,044 42,0 31,1 44,4 3,7%
484 20 15 32,3 0,041 45,0 31,0 41,3 3,3%
500 19 15 33,3 0,038 47,4 30,0 38,0 0,0%

(The line in bold is the recommended recipe for common use)


Description of the columns of the table:

Column Description
Ore Used How much ore you put into the furnace
CC Used How much charcoal you put into the furnace
Metal Yield How much metal you get out of the run
Ore Use/Metal How much ore it cost to make 1 metal
CC Cost/Metal How much charcoal it cost to make 1 metal
Metal Yield/Hour How much metal you produce in an hour
Metal Yield/1000 Ore How much metal you get out of 1000 ore
CC Cost/1000 Ore How much charcoal it costs to smelt 1000 ore
Net Gain: How much metal you've gained compared to the baseline formula (MetalYield = OreAmount*3/100)

It's recommended to simply use the 484 ore + 20 cc => 15 metal recipe unless you want to squeeze some extra mileage out of your ore at a significant increase in charcoal costs. If you do want to save significantly on your ore you will have to go to the extreme recipes such as 50 ore + 20 cc => 2 metal or even 17 ore + 20 cc => 1 metal. By using the most ore-efficient recipe it's possible to almost double the metal yield by paying more than 25 times the charcoal cost.

Operation

  • Holds up to 500 ore
  • Holds up to 20cc
  • Burns 1cc per minute for a maximum of 20 minutes
  • Current "fire and forget" recipes are :
  • 125 ore, 20cc yields 4 metal
  • 250 ore, 20cc yields 8 metal.

Testing

after fix

125 ore/ 20 cc => 4 metal

250 ore/ 20 cc => 8 metal

400 ore/ 20 cc => 12 metal

490 ore/ 20 cc => 15 metal

500 ore/ 20 cc => 15 metal

Blast Furnace

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