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Difference between revisions of "Gyration Cell"
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*Conjecture:1500/150=10 implies that 10 ore cooked for 15 minutes will yield 1 metal. But this is without rounding. With rounding, you get 5 ore yields 1 metal, 15 ore yields 2, ''n*10-5'' ore yields ''n'' metal, etc. in 15 minutes. Of course, with the cooking cost being 50 CC, extra efficiency comes at a high cost in the renewable charcoal. | *Conjecture:1500/150=10 implies that 10 ore cooked for 15 minutes will yield 1 metal. But this is without rounding. With rounding, you get 5 ore yields 1 metal, 15 ore yields 2, ''n*10-5'' ore yields ''n'' metal, etc. in 15 minutes. Of course, with the cooking cost being 50 CC, extra efficiency comes at a high cost in the renewable charcoal. | ||
| − | *Rounds Up: I put in 446 copper ore and got 45 copper. According to above formula, then 445 ore should have also yielded 45 copper. So in other words, loading 400-404 ore would yield 40 metal. Loading 405-409 would yield 41 metal. So it is best to load numbers ending with 0 or 5. - Cegaiel | + | *Rounds Up: Always load in numbers ending in 0 or 5. If you are loading the max of 1500, then load 1495 instead. It will still yield 150 iron. Load 95 (instead of 100) and you will get 10 iron. |
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| + | I put in 446 copper ore and got 45 copper. According to above formula, then 445 ore should have also yielded 45 copper. So in other words, loading 400-404 ore would yield 40 metal. Loading 405-409 would yield 41 metal. So it is best to load numbers ending with 0 or 5. - Cegaiel | ||
== Related Pages == | == Related Pages == | ||
Revision as of 08:01, 12 December 2009
| |
|---|---|
| Size | 7x7 |
| Where | Compound |
Source
This building becomes available after you have learned the Metallurgy 3 tech.
Cost
- 1000 Boards
- 500 Clay
- 250 Concrete
- 50 Copper Sheeting
- 12 Crucibles
- 20 Glass Pipe
- 100 Leather
- 50 Moon Steel
- 10 Pulleys
- 25 Tin Sheeting
Built in a Compound. Uses 7x7 cells.
Use
A Gyration Cell holds up to 1500 ore and 50 Charcoal.
1500 ore, 50 Charcoal for 15 minutes yields 150 metal.
750 ore, 50 Charcoal for 15 minutes yields 75 metal.
In general, X ore, 50 Charcoal for 15 minutes yields X/10 metal.
Be careful : if you open the gyration cell while functioning, all the ore and charcoal will be wasted, only the metal already produced will remain.
Yield
| Ore Used | CC Used | Metal Yield | Time opened | Ore Cost/Metal | |
|---|---|---|---|---|---|
| 1500 | 50 | 150 | 15 mins | 10 | |
| 100 | 50 | 10 | 15 mins | 10 | |
| 1000 | 50 | 100 | 15 mins | 10 |
- Conjecture:1500/150=10 implies that 10 ore cooked for 15 minutes will yield 1 metal. But this is without rounding. With rounding, you get 5 ore yields 1 metal, 15 ore yields 2, n*10-5 ore yields n metal, etc. in 15 minutes. Of course, with the cooking cost being 50 CC, extra efficiency comes at a high cost in the renewable charcoal.
- Rounds Up: Always load in numbers ending in 0 or 5. If you are loading the max of 1500, then load 1495 instead. It will still yield 150 iron. Load 95 (instead of 100) and you will get 10 iron.
I put in 446 copper ore and got 45 copper. According to above formula, then 445 ore should have also yielded 45 copper. So in other words, loading 400-404 ore would yield 40 metal. Loading 405-409 would yield 41 metal. So it is best to load numbers ending with 0 or 5. - Cegaiel
