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Difference between revisions of "Amusement Data"
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| − | + | KOOORGGG?GGGROOORGGG?GGGROGGGGGK | |
| + | length is 33, G-groups are longer, 5 total G's to be inserted in ? | ||
| + | |||
| + | Mutagen results show it '''cannot be length 33''', then 15th would be O and 16th G | ||
Ariella Solvent Data | Ariella Solvent Data | ||
RGGGGGG KOOORGG OGGGGGK OORGGGG GGGGGGR RGGGGGG OOORGGG | RGGGGGG KOOORGG OGGGGGK OORGGGG GGGGGGR RGGGGGG OOORGGG | ||
| − | GGGGGRO GGGGROG GGGGGGG GGGROGG GROGGGG | + | GGGGGRO GGGGROG GGGGGGG GGGROGG GROGGGG |
| + | |||
| + | after changing 8 or 9th gene to a Y : KOOORGGGggGR...; solvent results GYGG YGGG means at least 1 extra G in first G=group | ||
Latest revision as of 03:50, 13 October 2009
KOOORGGG?GGGROOORGGG?GGGROGGGGGK length is 33, G-groups are longer, 5 total G's to be inserted in ?
Mutagen results show it cannot be length 33, then 15th would be O and 16th G
Ariella Solvent Data RGGGGGG KOOORGG OGGGGGK OORGGGG GGGGGGR RGGGGGG OOORGGG GGGGGRO GGGGROG GGGGGGG GGGROGG GROGGGG
after changing 8 or 9th gene to a Y : KOOORGGGggGR...; solvent results GYGG YGGG means at least 1 extra G in first G=group
KOOORGG
OOORGGG
OORGGGG
ORGGGGG
RGGGGGG
?
GGGGGGG
GGGGGGR
GGGGGRO
missing
missing
GGROOO
missing
ROOORG
OOORGGG
OORGGGG
RGGGGGG
?
GGGGGGG
GGGGGGR
GGGGGRO
GGGGROG
GGGROGG
missing
GROGGGG
OGGGGGK
KOOORGGGGGGGROOORGGGGGGGROGGGGGK Three missing Gs, could be 6 Gs in one of the Gstrings
Made two crosses of Amusement8G/Appreciation2Y KU1 to put a Y in the middle of the Gs on Amusement. Solvent data for that cross below.
GGGGGG OOORGG GGGGRO GGROOY
KU1 should hit 41.67% to 44.12% on a genome, this time a Y. Looks like GGROOY used to be GGROOO. On a 29 length genome the Y (or third O) would hit on the 12th/13th gene which would put 5 Gs between KOOOR and ROOOR.
KOOORGGGGGGGROGGGGGK Note: solvents below show different, elongated genome now.
Made two crosses putting a Y in gene 7 and 18 of Amusement, in the middle of the two long G sequences. Solvent data for that cross below. KOOORGGGyGGROOORGGGyGGGROGGGGGK - assumption
OORGGG - 4 GGGGGK ORGGGY GGGGRO - 2 OOORGG ROOORG GGROGG RGGGYG GYGGGG RGGGYGG - 2 GGYGGGG - 2 GYGGGGR - 2
Aperio Solvent Data
OOORGGG GGGGGGR x2 OGGGGGK ROGGGGG GGGGGRO x2 ROOORG
Aperio Solvent Data (200 Milky trials)
(45.5%) (91) GGG 1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111 (04.0%) (08) GGK 11111111 (06.0%) (12) GGR 111111111111 (06.5%) (13) GRO 1111111111111 (03.5%) (07) KOO 1111111 (02.5%) (05) OGG 11111 (06.5%) (13) OOO 1111111111111 (06.0%) (12) OOR 111111111111 (08.0%) (16) ORG 1111111111111111 (06.5%) (13) RGG 1111111111111 (02.5%) (05) ROG 11111 (02.5%) (05) ROO 11111
Analysis (independent of the more complex solvents to validate the technique)
Assuming +/- 2.5% variance, all the non-GGG combinations fall within the same range with the marginal exception of ORG. Since both endpoints (which by definition will have 1 occurrence) are at the upper end of this range, I'm willing to expand the range to include ORG because we know the random number generation is weak and it's non-sensical to create a new bands of 2 occurrences to accommodate ORG when the endpoints would be present in that band. GGG appears 9x as often as any other sequence, which suggests 11 Gs in a row OR two strings of Gs. GGK terminates one of the GGG strings. GGR terminates another. It is possible that one or both could just be a double, but then we'd have to have repetitions to account for the GGG strings separately. OGG begins a GGG string. RGG starts another. Two strings of GGG(x) and GGG(y) are conclusive. I'm using (x), (y), and (z) to indicate repetitions of the sequence. In some single gene sequences, I'm referring to the repetitions of the same letter in the gene to give its length and I need to adopt a clearer notations like [z] - Aperio
KOO 1
OOO 1
OOR 1
ORG 1
RGG 1
GGG(x)
GGR 1
GRO 1
ROG 1
OGG 1
GGG(y)
GGK
Combined with more complex clues
RGG starts no less than 6 Gs. This accounts for at least 4 of out repetitions. OGG stats no more than 6 Gs because it's terminated by a K. This accounts for 3 of our 9 repetitions. We have a GGGGGGG[7] clue, so we know that RGG must lead to at least 5 of our repetitions. Since we have no expectation of a 3rd string of GGG(z), we must assume that RGG starts a sequence of 8 Gs to permit 6 repetitions. [POST-MORTEM] I have missed ROO in this analysis.
KOOORGGGGGGGGROGGGGGK
KOO 1
OOO 1
OOR 1
ORG 1
RGG 1
KOOORGG CONFIRMED
GGGGGGGG GGG(x=8)
OOORGGG CONFIRMED
OORGGGG CONFIRMED
RGGGGGG CONFIRMED
GGGGGGG LIKELY
GGGGGGG LIKELY(2)
GGR 1
GGGGGGR CONFIRMED
GRO 1
GGGGGRO CONFIRMED
ROG 1
GGGGROG CONFIRMED
OGG 1
GGGROGG CONFIRMED
GGGGG GGG(y=5)
GROGGGG CONFIRMED
OGGGGGK CONFIRMED
GGK
KOOORGGGGGGGGROGGGGGK
This is really tight, but ROOORG from my later Crystal trial is UNACCOUNTED FOR - Aperio
[POST-MORTEM] I still have missed ROO in this analysis.
This suggests another string of OOO to account for ROOORG.
OOR density supports this string. ROO density does not. ORG density DEFINITELY supports this but was overlooked intentionally.
This implies another RGG string which is supported, also.
If 8% is the 2nd band, then 44% is 11 repeats of GGG and 28% is 12 repeats
if 7.5% is the 2nd band, then 45% is 12 repeats. I lean towards 12 here.
11-12 GGG 1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111 1 GGK 11111111 2 GGR 111111111111 2 GRO 1111111111111 1 KOO 1111111 1 OGG 11111 2 OOO 1111111111111 2 OOR 111111111111 2 ORG 1111111111111111 2 RGG 1111111111111 1 ROG 11111 1 ROO 11111
KOOORGGGGGGROOORGGGGGGGROGGGGGK
KOOORGG
KOO 1
OOO 1
OOR 1
ORG 1
RGG 1
KOOORGGGGGGROOORGGGGGGGROGGGGGK
OORGGGG
KOOORGGGGGGROOORGGGGGGGROGGGGGK
RGGGGGG
GGG 1
GGG 2
GGG 3
GGG 4
KOOORGGGGGGROOORGGGGGGGROGGGGGK
GGGGGGR
GGR 1
KOOORGGGGGGROOORGGGGGGGROGGGGGK
GGGGGRO
GRO 1
KOOORGGGGGGROOORGGGGGGGROGGGGGK
ROOORG
ROO 1
OOO 2
OOR 2
ORG 2
KOOORGGGGGGROOORGGGGGGGROGGGGGK
OORGGGG
RGG 2
???????
KOOORGGGGGGROOORGGGGGGGROGGGGGK
RGGGGGG
GGG 5
GGG 6
GGG 7
GGG 8
KOOORGGGGGGROOORGGGGGGGROGGGGGK
GGGGGGG (GGGx5)
GGG 9
KOOORGGGGGGROOORGGGGGGGROGGGGGK
GGGGGGR
GGR 2
KOOORGGGGGGROOORGGGGGGGROGGGGGK
GGGGGRO
GRO 2
KOOORGGGGGGROOORGGGGGGGROGGGGGK
GGGGROG
ROG 1
KOOORGGGGGGROOORGGGGGGGROGGGGGK
GGGROGG
OGG 1
KOOORGGGGGGROOORGGGGGGGROGGGGGK
GROGGGG
GGG 10
GGG 11
???????
KOOORGGGGGGROOORGGGGGGGROGGGGGK
OGGGGGK (GGGx3)
GGG 12
GGK 1
KOOORGGGGGGROOORGGGGGGGROGGGGGK
