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Amusement Data
KOOORGGG?GGGROOORGGG?GGGROGGGGGK length is 33, G-groups are longer, 5 total G's to be inserted in ?
Mutagen results show it cannot be length 33, then 15th would be O and 16th G
Ariella Solvent Data RGGGGGG KOOORGG OGGGGGK OORGGGG GGGGGGR RGGGGGG OOORGGG GGGGGRO GGGGROG GGGGGGG GGGROGG GROGGGG
after changing 8 or 9th gene to a Y : KOOORGGGggGR...; solvent results GYGG YGGG means at least 1 extra G in first G=group
KOOORGG OOORGGG OORGGGG ORGGGGG RGGGGGG ? GGGGGGG GGGGGGR GGGGGRO missing missing GGROOO missing ROOORG OOORGGG OORGGGG RGGGGGG ? GGGGGGG GGGGGGR GGGGGRO GGGGROG GGGROGG missing GROGGGG OGGGGGK KOOORGGGGGGGROOORGGGGGGGROGGGGGK Three missing Gs, could be 6 Gs in one of the Gstrings
Made two crosses of Amusement8G/Appreciation2Y KU1 to put a Y in the middle of the Gs on Amusement. Solvent data for that cross below.
GGGGGG OOORGG GGGGRO GGROOY
KU1 should hit 41.67% to 44.12% on a genome, this time a Y. Looks like GGROOY used to be GGROOO. On a 29 length genome the Y (or third O) would hit on the 12th/13th gene which would put 5 Gs between KOOOR and ROOOR.
KOOORGGGGGGGROGGGGGK Note: solvents below show different, elongated genome now.
Made two crosses putting a Y in gene 7 and 18 of Amusement, in the middle of the two long G sequences. Solvent data for that cross below. KOOORGGGyGGROOORGGGyGGGROGGGGGK - assumption
OORGGG - 4 GGGGGK ORGGGY GGGGRO - 2 OOORGG ROOORG GGROGG RGGGYG GYGGGG RGGGYGG - 2 GGYGGGG - 2 GYGGGGR - 2
Aperio Solvent Data
OOORGGG GGGGGGR x2 OGGGGGK ROGGGGG GGGGGRO x2 ROOORG
Aperio Solvent Data (200 Milky trials)
(45.5%) (91) GGG 1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111 (04.0%) (08) GGK 11111111 (06.0%) (12) GGR 111111111111 (06.5%) (13) GRO 1111111111111 (03.5%) (07) KOO 1111111 (02.5%) (05) OGG 11111 (06.5%) (13) OOO 1111111111111 (06.0%) (12) OOR 111111111111 (08.0%) (16) ORG 1111111111111111 (06.5%) (13) RGG 1111111111111 (02.5%) (05) ROG 11111 (02.5%) (05) ROO 11111
Analysis (independent of the more complex solvents to validate the technique)
Assuming +/- 2.5% variance, all the non-GGG combinations fall within the same range with the marginal exception of ORG. Since both endpoints (which by definition will have 1 occurrence) are at the upper end of this range, I'm willing to expand the range to include ORG because we know the random number generation is weak and it's non-sensical to create a new bands of 2 occurrences to accommodate ORG when the endpoints would be present in that band. GGG appears 9x as often as any other sequence, which suggests 11 Gs in a row OR two strings of Gs. GGK terminates one of the GGG strings. GGR terminates another. It is possible that one or both could just be a double, but then we'd have to have repetitions to account for the GGG strings separately. OGG begins a GGG string. RGG starts another. Two strings of GGG(x) and GGG(y) are conclusive. I'm using (x), (y), and (z) to indicate repetitions of the sequence. In some single gene sequences, I'm referring to the repetitions of the same letter in the gene to give its length and I need to adopt a clearer notations like [z] - Aperio
KOO 1 OOO 1 OOR 1 ORG 1 RGG 1
GGG(x)
GGR 1 GRO 1 ROG 1 OGG 1
GGG(y)
GGK
Combined with more complex clues
RGG starts no less than 6 Gs. This accounts for at least 4 of out repetitions. OGG stats no more than 6 Gs because it's terminated by a K. This accounts for 3 of our 9 repetitions. We have a GGGGGGG[7] clue, so we know that RGG must lead to at least 5 of our repetitions. Since we have no expectation of a 3rd string of GGG(z), we must assume that RGG starts a sequence of 8 Gs to permit 6 repetitions. [POST-MORTEM] I have missed ROO in this analysis.
KOOORGGGGGGGGROGGGGGK KOO 1 OOO 1 OOR 1 ORG 1 RGG 1 KOOORGG CONFIRMED GGGGGGGG GGG(x=8) OOORGGG CONFIRMED OORGGGG CONFIRMED RGGGGGG CONFIRMED GGGGGGG LIKELY GGGGGGG LIKELY(2) GGR 1 GGGGGGR CONFIRMED GRO 1 GGGGGRO CONFIRMED ROG 1 GGGGROG CONFIRMED OGG 1 GGGROGG CONFIRMED GGGGG GGG(y=5) GROGGGG CONFIRMED OGGGGGK CONFIRMED GGK KOOORGGGGGGGGROGGGGGK
This is really tight, but ROOORG from my later Crystal trial is UNACCOUNTED FOR - Aperio
[POST-MORTEM] I still have missed ROO in this analysis.
This suggests another string of OOO to account for ROOORG.
OOR density supports this string. ROO density does not. ORG density DEFINITELY supports this but was overlooked intentionally.
This implies another RGG string which is supported, also.
If 8% is the 2nd band, then 44% is 11 repeats of GGG and 28% is 12 repeats
if 7.5% is the 2nd band, then 45% is 12 repeats. I lean towards 12 here.
11-12 GGG 1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111 1 GGK 11111111 2 GGR 111111111111 2 GRO 1111111111111 1 KOO 1111111 1 OGG 11111 2 OOO 1111111111111 2 OOR 111111111111 2 ORG 1111111111111111 2 RGG 1111111111111 1 ROG 11111 1 ROO 11111
KOOORGGGGGGROOORGGGGGGGROGGGGGK KOOORGG KOO 1 OOO 1 OOR 1 ORG 1 RGG 1 KOOORGGGGGGROOORGGGGGGGROGGGGGK OORGGGG KOOORGGGGGGROOORGGGGGGGROGGGGGK RGGGGGG GGG 1 GGG 2 GGG 3 GGG 4 KOOORGGGGGGROOORGGGGGGGROGGGGGK GGGGGGR GGR 1 KOOORGGGGGGROOORGGGGGGGROGGGGGK GGGGGRO GRO 1 KOOORGGGGGGROOORGGGGGGGROGGGGGK ROOORG ROO 1 OOO 2 OOR 2 ORG 2 KOOORGGGGGGROOORGGGGGGGROGGGGGK OORGGGG RGG 2 ??????? KOOORGGGGGGROOORGGGGGGGROGGGGGK RGGGGGG GGG 5 GGG 6 GGG 7 GGG 8 KOOORGGGGGGROOORGGGGGGGROGGGGGK GGGGGGG (GGGx5) GGG 9 KOOORGGGGGGROOORGGGGGGGROGGGGGK GGGGGGR GGR 2 KOOORGGGGGGROOORGGGGGGGROGGGGGK GGGGGRO GRO 2 KOOORGGGGGGROOORGGGGGGGROGGGGGK GGGGROG ROG 1 KOOORGGGGGGROOORGGGGGGGROGGGGGK GGGROGG OGG 1 KOOORGGGGGGROOORGGGGGGGROGGGGGK GROGGGG GGG 10 GGG 11 ??????? KOOORGGGGGGROOORGGGGGGGROGGGGGK OGGGGGK (GGGx3) GGG 12 GGK 1 KOOORGGGGGGROOORGGGGGGGROGGGGGK