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Difference between revisions of "Gyration Cell"

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{{Template:BuildingInfo|image=Gyro.png|size=7x7|where=[[where::Compound]]
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{{Template:BuildingInfo|image=Gyro.png|size=7x7|where=[[where::Compound]]|description=Non-Polluting ore smelting.}}  
|description=Non-Polluting ore smelting.
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}}  
 
 
== Source ==
 
== Source ==
 
This building becomes available after you have learned the [[requires::Metallurgy 3]] tech.   
 
This building becomes available after you have learned the [[requires::Metallurgy 3]] tech.   
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== Use ==
 
== Use ==
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* Smelt [[Copper Ore]] to produce [[produces::Copper]]
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* Smelt [[Iron Ore]] to produce [[produces::Iron]]
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* Smelt [[Tin Ore]] to produce [[produces::Tin]]
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* Smelt [[Lead Ore]] to produce [[produces::Lead]]
  
A Gyration Cell holds up to 1500 ore and 50 [[fuel::Charcoal]].
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Uses up to 50 [[fuel::Charcoal]] for fuel.
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 +
After firing, the metal will be ready in 15 minutes (if fully loaded with Charcoal) and will stay in the furnace until removed.
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 +
== Operation ==
 +
A Gyration Cell holds up to 1500 ore and 50 [[Charcoal]].
  
 
1500 ore, 50 Charcoal for 15 minutes yields 150 metal.<br>
 
1500 ore, 50 Charcoal for 15 minutes yields 150 metal.<br>
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Be careful : if you open the gyration cell while functioning, all the ore and charcoal will be wasted, only the metal already produced will remain.
 
Be careful : if you open the gyration cell while functioning, all the ore and charcoal will be wasted, only the metal already produced will remain.
  
== Yield ==
 
  
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=== Yield ===
 
{| border="1"
 
{| border="1"
 
! Ore Used!! CC Used !! Metal Yield !! Time opened !! Ore Cost/Metal
 
! Ore Used!! CC Used !! Metal Yield !! Time opened !! Ore Cost/Metal
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|}
 
|}
  
*Conjecture:1500/150=10 implies that 10 ore cooked for 15 minutes will yield 1 metal.  But this is without rounding.  With rounding, you get 5 ore yields 1 metal, 15 ore yields 2, ''n*10-5'' ore yields ''n'' metal, etc. in 15 minutes.  Of course, with the cooking cost being 50 CC, extra efficiency comes at a high cost in the renewable charcoal.
 
  
*Rounds Up: I put in 446 copper ore and got 45 copperAccording to above formula, then 445 ore should have also yielded 45 copperSo in other words, loading 400-404 ore would yield 40 metal. Loading 405-409 would yield 41 metal. So it is best to load numbers ending with 0 or 5. - Cegaiel
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*<b>Conjecture:</b> 1500/150=10 implies that 10 ore cooked for 15 minutes will yield 1 metal.  But this is without roundingWith rounding, you get 5 ore yields 1 metal, 15 ore yields 2, ''n*10-5'' ore yields ''n'' metal, etc. in 15 minutesOf course, with the cooking cost being 50 CC, extra efficiency comes at a high cost in the renewable charcoal.
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 +
 
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*<b>Rounds Up:</b> Always load in numbers ending in 0 or 5. If you are loading the max of 1500, then load 1495 instead.  It will still yield 150 iron.  Load 95 (instead of 100) and you will get 10 iron. Never load with numbers ending with 1-4 else it still rounds down and you wasted your extra 1-4 ore. Loading a number ending with 6-9 will also waste ore. - Cegaiel
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 +
 
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<b>Optimal Yield Chart:</b>
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 +
{| border="1"
 +
! Ore Used!! CC Used !! Metal Yield !! Time opened !! Ore Cost/Metal
 +
|-
 +
| 1495
 +
| 50
 +
| 150
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| 15 mins
 +
| 10
 +
|
 +
|-
 +
| 95
 +
| 50
 +
| 10
 +
| 15 mins
 +
| 10
 +
|
 +
|-
 +
| 995
 +
| 50
 +
| 100
 +
| 15 mins
 +
| 10
 +
|
 +
|-  
 +
|}
 +
 
 +
You don't need to load the exact ore amounts in charts above, just remember its 10% metal of the amount of ore you load. You still always use 50cc. Again, always load in a number ending with 0 or 5 for optimal yield.
 +
 
  
 
== Related Pages ==
 
== Related Pages ==
 
* [[Furnaces]]
 
* [[Furnaces]]
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{{PublicUsableOnes}}
 
{{PublicUsableOnes}}
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[[Category:Buildings]]
 
[[Category:Buildings]]
 +
[[Category:Furnaces]]

Latest revision as of 01:46, 19 April 2010

Gyro.png
Size 7x7
Where Compound




Source

This building becomes available after you have learned the Metallurgy 3 tech.

Cost

Built in a Compound. Uses 7x7 cells.

Use

Uses up to 50 Charcoal for fuel.

After firing, the metal will be ready in 15 minutes (if fully loaded with Charcoal) and will stay in the furnace until removed.

Operation

A Gyration Cell holds up to 1500 ore and 50 Charcoal.

1500 ore, 50 Charcoal for 15 minutes yields 150 metal.
750 ore, 50 Charcoal for 15 minutes yields 75 metal.
In general, X ore, 50 Charcoal for 15 minutes yields X/10 metal.

Be careful : if you open the gyration cell while functioning, all the ore and charcoal will be wasted, only the metal already produced will remain.


Yield

Ore Used CC Used Metal Yield Time opened Ore Cost/Metal
1500 50 150 15 mins 10
100 50 10 15 mins 10
1000 50 100 15 mins 10


  • Conjecture: 1500/150=10 implies that 10 ore cooked for 15 minutes will yield 1 metal. But this is without rounding. With rounding, you get 5 ore yields 1 metal, 15 ore yields 2, n*10-5 ore yields n metal, etc. in 15 minutes. Of course, with the cooking cost being 50 CC, extra efficiency comes at a high cost in the renewable charcoal.


  • Rounds Up: Always load in numbers ending in 0 or 5. If you are loading the max of 1500, then load 1495 instead. It will still yield 150 iron. Load 95 (instead of 100) and you will get 10 iron. Never load with numbers ending with 1-4 else it still rounds down and you wasted your extra 1-4 ore. Loading a number ending with 6-9 will also waste ore. - Cegaiel


Optimal Yield Chart:

Ore Used CC Used Metal Yield Time opened Ore Cost/Metal
1495 50 150 15 mins 10
95 50 10 15 mins 10
995 50 100 15 mins 10

You don't need to load the exact ore amounts in charts above, just remember its 10% metal of the amount of ore you load. You still always use 50cc. Again, always load in a number ending with 0 or 5 for optimal yield.


Related Pages


Public usable ones